Optimal. Leaf size=612 \[ \frac {15 i a^3 (e \sec (c+d x))^{3/2}}{8 d \sqrt {a+i a \tan (c+d x)}}-\frac {15 i a^{7/2} e^{3/2} \text {ArcTan}\left (1-\frac {\sqrt {2} \sqrt {e} \sqrt {a-i a \tan (c+d x)}}{\sqrt {a} \sqrt {e \sec (c+d x)}}\right ) \sec (c+d x)}{8 \sqrt {2} d \sqrt {a-i a \tan (c+d x)} \sqrt {a+i a \tan (c+d x)}}+\frac {15 i a^{7/2} e^{3/2} \text {ArcTan}\left (1+\frac {\sqrt {2} \sqrt {e} \sqrt {a-i a \tan (c+d x)}}{\sqrt {a} \sqrt {e \sec (c+d x)}}\right ) \sec (c+d x)}{8 \sqrt {2} d \sqrt {a-i a \tan (c+d x)} \sqrt {a+i a \tan (c+d x)}}+\frac {15 i a^{7/2} e^{3/2} \log \left (a-\frac {\sqrt {2} \sqrt {a} \sqrt {e} \sqrt {a-i a \tan (c+d x)}}{\sqrt {e \sec (c+d x)}}+\cos (c+d x) (a-i a \tan (c+d x))\right ) \sec (c+d x)}{16 \sqrt {2} d \sqrt {a-i a \tan (c+d x)} \sqrt {a+i a \tan (c+d x)}}-\frac {15 i a^{7/2} e^{3/2} \log \left (a+\frac {\sqrt {2} \sqrt {a} \sqrt {e} \sqrt {a-i a \tan (c+d x)}}{\sqrt {e \sec (c+d x)}}+\cos (c+d x) (a-i a \tan (c+d x))\right ) \sec (c+d x)}{16 \sqrt {2} d \sqrt {a-i a \tan (c+d x)} \sqrt {a+i a \tan (c+d x)}}+\frac {3 i a^2 (e \sec (c+d x))^{3/2} \sqrt {a+i a \tan (c+d x)}}{4 d}+\frac {i a (e \sec (c+d x))^{3/2} (a+i a \tan (c+d x))^{3/2}}{3 d} \]
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Rubi [A]
time = 0.48, antiderivative size = 612, normalized size of antiderivative = 1.00, number of steps
used = 14, number of rules used = 9, integrand size = 30, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.300, Rules used = {3579, 3580,
3576, 303, 1176, 631, 210, 1179, 642} \begin {gather*} -\frac {15 i a^{7/2} e^{3/2} \sec (c+d x) \text {ArcTan}\left (1-\frac {\sqrt {2} \sqrt {e} \sqrt {a-i a \tan (c+d x)}}{\sqrt {a} \sqrt {e \sec (c+d x)}}\right )}{8 \sqrt {2} d \sqrt {a-i a \tan (c+d x)} \sqrt {a+i a \tan (c+d x)}}+\frac {15 i a^{7/2} e^{3/2} \sec (c+d x) \text {ArcTan}\left (1+\frac {\sqrt {2} \sqrt {e} \sqrt {a-i a \tan (c+d x)}}{\sqrt {a} \sqrt {e \sec (c+d x)}}\right )}{8 \sqrt {2} d \sqrt {a-i a \tan (c+d x)} \sqrt {a+i a \tan (c+d x)}}+\frac {15 i a^{7/2} e^{3/2} \sec (c+d x) \log \left (-\frac {\sqrt {2} \sqrt {a} \sqrt {e} \sqrt {a-i a \tan (c+d x)}}{\sqrt {e \sec (c+d x)}}+\cos (c+d x) (a-i a \tan (c+d x))+a\right )}{16 \sqrt {2} d \sqrt {a-i a \tan (c+d x)} \sqrt {a+i a \tan (c+d x)}}-\frac {15 i a^{7/2} e^{3/2} \sec (c+d x) \log \left (\frac {\sqrt {2} \sqrt {a} \sqrt {e} \sqrt {a-i a \tan (c+d x)}}{\sqrt {e \sec (c+d x)}}+\cos (c+d x) (a-i a \tan (c+d x))+a\right )}{16 \sqrt {2} d \sqrt {a-i a \tan (c+d x)} \sqrt {a+i a \tan (c+d x)}}+\frac {15 i a^3 (e \sec (c+d x))^{3/2}}{8 d \sqrt {a+i a \tan (c+d x)}}+\frac {3 i a^2 \sqrt {a+i a \tan (c+d x)} (e \sec (c+d x))^{3/2}}{4 d}+\frac {i a (a+i a \tan (c+d x))^{3/2} (e \sec (c+d x))^{3/2}}{3 d} \end {gather*}
Antiderivative was successfully verified.
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Rule 210
Rule 303
Rule 631
Rule 642
Rule 1176
Rule 1179
Rule 3576
Rule 3579
Rule 3580
Rubi steps
\begin {align*} \int (e \sec (c+d x))^{3/2} (a+i a \tan (c+d x))^{5/2} \, dx &=\frac {i a (e \sec (c+d x))^{3/2} (a+i a \tan (c+d x))^{3/2}}{3 d}+\frac {1}{2} (3 a) \int (e \sec (c+d x))^{3/2} (a+i a \tan (c+d x))^{3/2} \, dx\\ &=\frac {3 i a^2 (e \sec (c+d x))^{3/2} \sqrt {a+i a \tan (c+d x)}}{4 d}+\frac {i a (e \sec (c+d x))^{3/2} (a+i a \tan (c+d x))^{3/2}}{3 d}+\frac {1}{8} \left (15 a^2\right ) \int (e \sec (c+d x))^{3/2} \sqrt {a+i a \tan (c+d x)} \, dx\\ &=\frac {15 i a^3 (e \sec (c+d x))^{3/2}}{8 d \sqrt {a+i a \tan (c+d x)}}+\frac {3 i a^2 (e \sec (c+d x))^{3/2} \sqrt {a+i a \tan (c+d x)}}{4 d}+\frac {i a (e \sec (c+d x))^{3/2} (a+i a \tan (c+d x))^{3/2}}{3 d}+\frac {1}{16} \left (15 a^3\right ) \int \frac {(e \sec (c+d x))^{3/2}}{\sqrt {a+i a \tan (c+d x)}} \, dx\\ &=\frac {15 i a^3 (e \sec (c+d x))^{3/2}}{8 d \sqrt {a+i a \tan (c+d x)}}+\frac {3 i a^2 (e \sec (c+d x))^{3/2} \sqrt {a+i a \tan (c+d x)}}{4 d}+\frac {i a (e \sec (c+d x))^{3/2} (a+i a \tan (c+d x))^{3/2}}{3 d}+\frac {\left (15 a^3 e \sec (c+d x)\right ) \int \sqrt {e \sec (c+d x)} \sqrt {a-i a \tan (c+d x)} \, dx}{16 \sqrt {a-i a \tan (c+d x)} \sqrt {a+i a \tan (c+d x)}}\\ &=\frac {15 i a^3 (e \sec (c+d x))^{3/2}}{8 d \sqrt {a+i a \tan (c+d x)}}+\frac {3 i a^2 (e \sec (c+d x))^{3/2} \sqrt {a+i a \tan (c+d x)}}{4 d}+\frac {i a (e \sec (c+d x))^{3/2} (a+i a \tan (c+d x))^{3/2}}{3 d}+\frac {\left (15 i a^4 e^3 \sec (c+d x)\right ) \text {Subst}\left (\int \frac {x^2}{a^2+e^2 x^4} \, dx,x,\frac {\sqrt {a-i a \tan (c+d x)}}{\sqrt {e \sec (c+d x)}}\right )}{4 d \sqrt {a-i a \tan (c+d x)} \sqrt {a+i a \tan (c+d x)}}\\ &=\frac {15 i a^3 (e \sec (c+d x))^{3/2}}{8 d \sqrt {a+i a \tan (c+d x)}}+\frac {3 i a^2 (e \sec (c+d x))^{3/2} \sqrt {a+i a \tan (c+d x)}}{4 d}+\frac {i a (e \sec (c+d x))^{3/2} (a+i a \tan (c+d x))^{3/2}}{3 d}-\frac {\left (15 i a^4 e^2 \sec (c+d x)\right ) \text {Subst}\left (\int \frac {a-e x^2}{a^2+e^2 x^4} \, dx,x,\frac {\sqrt {a-i a \tan (c+d x)}}{\sqrt {e \sec (c+d x)}}\right )}{8 d \sqrt {a-i a \tan (c+d x)} \sqrt {a+i a \tan (c+d x)}}+\frac {\left (15 i a^4 e^2 \sec (c+d x)\right ) \text {Subst}\left (\int \frac {a+e x^2}{a^2+e^2 x^4} \, dx,x,\frac {\sqrt {a-i a \tan (c+d x)}}{\sqrt {e \sec (c+d x)}}\right )}{8 d \sqrt {a-i a \tan (c+d x)} \sqrt {a+i a \tan (c+d x)}}\\ &=\frac {15 i a^3 (e \sec (c+d x))^{3/2}}{8 d \sqrt {a+i a \tan (c+d x)}}+\frac {3 i a^2 (e \sec (c+d x))^{3/2} \sqrt {a+i a \tan (c+d x)}}{4 d}+\frac {i a (e \sec (c+d x))^{3/2} (a+i a \tan (c+d x))^{3/2}}{3 d}+\frac {\left (15 i a^4 e \sec (c+d x)\right ) \text {Subst}\left (\int \frac {1}{\frac {a}{e}-\frac {\sqrt {2} \sqrt {a} x}{\sqrt {e}}+x^2} \, dx,x,\frac {\sqrt {a-i a \tan (c+d x)}}{\sqrt {e \sec (c+d x)}}\right )}{16 d \sqrt {a-i a \tan (c+d x)} \sqrt {a+i a \tan (c+d x)}}+\frac {\left (15 i a^4 e \sec (c+d x)\right ) \text {Subst}\left (\int \frac {1}{\frac {a}{e}+\frac {\sqrt {2} \sqrt {a} x}{\sqrt {e}}+x^2} \, dx,x,\frac {\sqrt {a-i a \tan (c+d x)}}{\sqrt {e \sec (c+d x)}}\right )}{16 d \sqrt {a-i a \tan (c+d x)} \sqrt {a+i a \tan (c+d x)}}+\frac {\left (15 i a^{7/2} e^{3/2} \sec (c+d x)\right ) \text {Subst}\left (\int \frac {\frac {\sqrt {2} \sqrt {a}}{\sqrt {e}}+2 x}{-\frac {a}{e}-\frac {\sqrt {2} \sqrt {a} x}{\sqrt {e}}-x^2} \, dx,x,\frac {\sqrt {a-i a \tan (c+d x)}}{\sqrt {e \sec (c+d x)}}\right )}{16 \sqrt {2} d \sqrt {a-i a \tan (c+d x)} \sqrt {a+i a \tan (c+d x)}}+\frac {\left (15 i a^{7/2} e^{3/2} \sec (c+d x)\right ) \text {Subst}\left (\int \frac {\frac {\sqrt {2} \sqrt {a}}{\sqrt {e}}-2 x}{-\frac {a}{e}+\frac {\sqrt {2} \sqrt {a} x}{\sqrt {e}}-x^2} \, dx,x,\frac {\sqrt {a-i a \tan (c+d x)}}{\sqrt {e \sec (c+d x)}}\right )}{16 \sqrt {2} d \sqrt {a-i a \tan (c+d x)} \sqrt {a+i a \tan (c+d x)}}\\ &=\frac {15 i a^3 (e \sec (c+d x))^{3/2}}{8 d \sqrt {a+i a \tan (c+d x)}}+\frac {15 i a^{7/2} e^{3/2} \log \left (a-\frac {\sqrt {2} \sqrt {a} \sqrt {e} \sqrt {a-i a \tan (c+d x)}}{\sqrt {e \sec (c+d x)}}+\cos (c+d x) (a-i a \tan (c+d x))\right ) \sec (c+d x)}{16 \sqrt {2} d \sqrt {a-i a \tan (c+d x)} \sqrt {a+i a \tan (c+d x)}}-\frac {15 i a^{7/2} e^{3/2} \log \left (a+\frac {\sqrt {2} \sqrt {a} \sqrt {e} \sqrt {a-i a \tan (c+d x)}}{\sqrt {e \sec (c+d x)}}+\cos (c+d x) (a-i a \tan (c+d x))\right ) \sec (c+d x)}{16 \sqrt {2} d \sqrt {a-i a \tan (c+d x)} \sqrt {a+i a \tan (c+d x)}}+\frac {3 i a^2 (e \sec (c+d x))^{3/2} \sqrt {a+i a \tan (c+d x)}}{4 d}+\frac {i a (e \sec (c+d x))^{3/2} (a+i a \tan (c+d x))^{3/2}}{3 d}+\frac {\left (15 i a^{7/2} e^{3/2} \sec (c+d x)\right ) \text {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,1-\frac {\sqrt {2} \sqrt {e} \sqrt {a-i a \tan (c+d x)}}{\sqrt {a} \sqrt {e \sec (c+d x)}}\right )}{8 \sqrt {2} d \sqrt {a-i a \tan (c+d x)} \sqrt {a+i a \tan (c+d x)}}-\frac {\left (15 i a^{7/2} e^{3/2} \sec (c+d x)\right ) \text {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,1+\frac {\sqrt {2} \sqrt {e} \sqrt {a-i a \tan (c+d x)}}{\sqrt {a} \sqrt {e \sec (c+d x)}}\right )}{8 \sqrt {2} d \sqrt {a-i a \tan (c+d x)} \sqrt {a+i a \tan (c+d x)}}\\ &=\frac {15 i a^3 (e \sec (c+d x))^{3/2}}{8 d \sqrt {a+i a \tan (c+d x)}}-\frac {15 i a^{7/2} e^{3/2} \tan ^{-1}\left (1-\frac {\sqrt {2} \sqrt {e} \sqrt {a-i a \tan (c+d x)}}{\sqrt {a} \sqrt {e \sec (c+d x)}}\right ) \sec (c+d x)}{8 \sqrt {2} d \sqrt {a-i a \tan (c+d x)} \sqrt {a+i a \tan (c+d x)}}+\frac {15 i a^{7/2} e^{3/2} \tan ^{-1}\left (1+\frac {\sqrt {2} \sqrt {e} \sqrt {a-i a \tan (c+d x)}}{\sqrt {a} \sqrt {e \sec (c+d x)}}\right ) \sec (c+d x)}{8 \sqrt {2} d \sqrt {a-i a \tan (c+d x)} \sqrt {a+i a \tan (c+d x)}}+\frac {15 i a^{7/2} e^{3/2} \log \left (a-\frac {\sqrt {2} \sqrt {a} \sqrt {e} \sqrt {a-i a \tan (c+d x)}}{\sqrt {e \sec (c+d x)}}+\cos (c+d x) (a-i a \tan (c+d x))\right ) \sec (c+d x)}{16 \sqrt {2} d \sqrt {a-i a \tan (c+d x)} \sqrt {a+i a \tan (c+d x)}}-\frac {15 i a^{7/2} e^{3/2} \log \left (a+\frac {\sqrt {2} \sqrt {a} \sqrt {e} \sqrt {a-i a \tan (c+d x)}}{\sqrt {e \sec (c+d x)}}+\cos (c+d x) (a-i a \tan (c+d x))\right ) \sec (c+d x)}{16 \sqrt {2} d \sqrt {a-i a \tan (c+d x)} \sqrt {a+i a \tan (c+d x)}}+\frac {3 i a^2 (e \sec (c+d x))^{3/2} \sqrt {a+i a \tan (c+d x)}}{4 d}+\frac {i a (e \sec (c+d x))^{3/2} (a+i a \tan (c+d x))^{3/2}}{3 d}\\ \end {align*}
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Mathematica [B] Both result and optimal contain complex but leaf count is larger than twice
the leaf count of optimal. \(11411\) vs. \(2(612)=1224\).
time = 58.71, size = 11411, normalized size = 18.65 \begin {gather*} \text {Result too large to show} \end {gather*}
Warning: Unable to verify antiderivative.
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Maple [A]
time = 1.00, size = 424, normalized size = 0.69
method | result | size |
default | \(\frac {\left (-1+\cos \left (d x +c \right )\right )^{2} \left (45 i \arctanh \left (\frac {\sqrt {\frac {1}{1+\cos \left (d x +c \right )}}\, \left (\cos \left (d x +c \right )+1+\sin \left (d x +c \right )\right )}{2}\right ) \left (\cos ^{3}\left (d x +c \right )\right )-45 i \arctanh \left (\frac {\sqrt {\frac {1}{1+\cos \left (d x +c \right )}}\, \left (\cos \left (d x +c \right )+1-\sin \left (d x +c \right )\right )}{2}\right ) \left (\cos ^{3}\left (d x +c \right )\right )+90 i \sqrt {\frac {1}{1+\cos \left (d x +c \right )}}\, \left (\cos ^{2}\left (d x +c \right )\right ) \sin \left (d x +c \right )-68 i \sqrt {\frac {1}{1+\cos \left (d x +c \right )}}\, \cos \left (d x +c \right ) \sin \left (d x +c \right )+45 \arctanh \left (\frac {\sqrt {\frac {1}{1+\cos \left (d x +c \right )}}\, \left (\cos \left (d x +c \right )+1+\sin \left (d x +c \right )\right )}{2}\right ) \left (\cos ^{3}\left (d x +c \right )\right )+45 \arctanh \left (\frac {\sqrt {\frac {1}{1+\cos \left (d x +c \right )}}\, \left (\cos \left (d x +c \right )+1-\sin \left (d x +c \right )\right )}{2}\right ) \left (\cos ^{3}\left (d x +c \right )\right )-90 \sqrt {\frac {1}{1+\cos \left (d x +c \right )}}\, \left (\cos ^{3}\left (d x +c \right )\right )-16 i \sin \left (d x +c \right ) \sqrt {\frac {1}{1+\cos \left (d x +c \right )}}-158 \sqrt {\frac {1}{1+\cos \left (d x +c \right )}}\, \left (\cos ^{2}\left (d x +c \right )\right )-52 \cos \left (d x +c \right ) \sqrt {\frac {1}{1+\cos \left (d x +c \right )}}+16 \sqrt {\frac {1}{1+\cos \left (d x +c \right )}}\right ) \sqrt {\frac {a \left (i \sin \left (d x +c \right )+\cos \left (d x +c \right )\right )}{\cos \left (d x +c \right )}}\, \left (\frac {e}{\cos \left (d x +c \right )}\right )^{\frac {3}{2}} a^{2}}{48 d \left (i \sin \left (d x +c \right )+\cos \left (d x +c \right )-1\right ) \cos \left (d x +c \right ) \sin \left (d x +c \right )^{3} \left (\frac {1}{1+\cos \left (d x +c \right )}\right )^{\frac {3}{2}}}\) | \(424\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [B] Both result and optimal contain complex but leaf count of result is larger than
twice the leaf count of optimal. 2914 vs. \(2 (434) = 868\).
time = 0.81, size = 2914, normalized size = 4.76 \begin {gather*} \text {Too large to display} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 0.40, size = 608, normalized size = 0.99 \begin {gather*} \frac {6 \, \sqrt {\frac {225 i \, a^{5} e^{3}}{64 \, d^{2}}} {\left (d e^{\left (4 i \, d x + 4 i \, c\right )} + 2 \, d e^{\left (2 i \, d x + 2 i \, c\right )} + d\right )} \log \left (\frac {2 \, {\left (\frac {15 \, {\left (a^{2} e^{\frac {3}{2}} + a^{2} e^{\left (2 i \, d x + 2 i \, c + \frac {3}{2}\right )}\right )} \sqrt {\frac {a}{e^{\left (2 i \, d x + 2 i \, c\right )} + 1}} e^{\left (\frac {1}{2} i \, d x + \frac {1}{2} i \, c\right )}}{\sqrt {e^{\left (2 i \, d x + 2 i \, c\right )} + 1}} + 8 i \, \sqrt {\frac {225 i \, a^{5} e^{3}}{64 \, d^{2}}} d\right )} e^{\left (-\frac {3}{2}\right )}}{15 \, a^{2}}\right ) - 6 \, \sqrt {\frac {225 i \, a^{5} e^{3}}{64 \, d^{2}}} {\left (d e^{\left (4 i \, d x + 4 i \, c\right )} + 2 \, d e^{\left (2 i \, d x + 2 i \, c\right )} + d\right )} \log \left (\frac {2 \, {\left (\frac {15 \, {\left (a^{2} e^{\frac {3}{2}} + a^{2} e^{\left (2 i \, d x + 2 i \, c + \frac {3}{2}\right )}\right )} \sqrt {\frac {a}{e^{\left (2 i \, d x + 2 i \, c\right )} + 1}} e^{\left (\frac {1}{2} i \, d x + \frac {1}{2} i \, c\right )}}{\sqrt {e^{\left (2 i \, d x + 2 i \, c\right )} + 1}} - 8 i \, \sqrt {\frac {225 i \, a^{5} e^{3}}{64 \, d^{2}}} d\right )} e^{\left (-\frac {3}{2}\right )}}{15 \, a^{2}}\right ) + 6 \, \sqrt {-\frac {225 i \, a^{5} e^{3}}{64 \, d^{2}}} {\left (d e^{\left (4 i \, d x + 4 i \, c\right )} + 2 \, d e^{\left (2 i \, d x + 2 i \, c\right )} + d\right )} \log \left (\frac {2 \, {\left (\frac {15 \, {\left (a^{2} e^{\frac {3}{2}} + a^{2} e^{\left (2 i \, d x + 2 i \, c + \frac {3}{2}\right )}\right )} \sqrt {\frac {a}{e^{\left (2 i \, d x + 2 i \, c\right )} + 1}} e^{\left (\frac {1}{2} i \, d x + \frac {1}{2} i \, c\right )}}{\sqrt {e^{\left (2 i \, d x + 2 i \, c\right )} + 1}} + 8 i \, \sqrt {-\frac {225 i \, a^{5} e^{3}}{64 \, d^{2}}} d\right )} e^{\left (-\frac {3}{2}\right )}}{15 \, a^{2}}\right ) - 6 \, \sqrt {-\frac {225 i \, a^{5} e^{3}}{64 \, d^{2}}} {\left (d e^{\left (4 i \, d x + 4 i \, c\right )} + 2 \, d e^{\left (2 i \, d x + 2 i \, c\right )} + d\right )} \log \left (\frac {2 \, {\left (\frac {15 \, {\left (a^{2} e^{\frac {3}{2}} + a^{2} e^{\left (2 i \, d x + 2 i \, c + \frac {3}{2}\right )}\right )} \sqrt {\frac {a}{e^{\left (2 i \, d x + 2 i \, c\right )} + 1}} e^{\left (\frac {1}{2} i \, d x + \frac {1}{2} i \, c\right )}}{\sqrt {e^{\left (2 i \, d x + 2 i \, c\right )} + 1}} - 8 i \, \sqrt {-\frac {225 i \, a^{5} e^{3}}{64 \, d^{2}}} d\right )} e^{\left (-\frac {3}{2}\right )}}{15 \, a^{2}}\right ) + \frac {{\left (45 i \, a^{2} e^{\frac {3}{2}} + 113 i \, a^{2} e^{\left (4 i \, d x + 4 i \, c + \frac {3}{2}\right )} + 126 i \, a^{2} e^{\left (2 i \, d x + 2 i \, c + \frac {3}{2}\right )}\right )} \sqrt {\frac {a}{e^{\left (2 i \, d x + 2 i \, c\right )} + 1}} e^{\left (\frac {1}{2} i \, d x + \frac {1}{2} i \, c\right )}}{\sqrt {e^{\left (2 i \, d x + 2 i \, c\right )} + 1}}}{12 \, {\left (d e^{\left (4 i \, d x + 4 i \, c\right )} + 2 \, d e^{\left (2 i \, d x + 2 i \, c\right )} + d\right )}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-2)]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Exception raised: SystemError} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.00 \begin {gather*} \int {\left (\frac {e}{\cos \left (c+d\,x\right )}\right )}^{3/2}\,{\left (a+a\,\mathrm {tan}\left (c+d\,x\right )\,1{}\mathrm {i}\right )}^{5/2} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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